Collect a request to send to Chrome? example of another API https://api.themoviedb.org/3/discover/movie?api_key=84f0f3a7bd08769b95016fc25a80a3ef&vote_count.gte=1000 How to do it also only with your API?
the url is:
for pizzas= url: ‘https://pizza-and-desserts.p.rapidapi.com/pizzas’
for desserts= url: ‘https://pizza-and-desserts.p.rapidapi.com/desserts’
and send headers also with your get request
headers: { ‘X-RapidAPI-Host’: ‘pizza-and-desserts.p.rapidapi.com’, ‘X-RapidAPI-Key’: your rapid api key
example:
fetch(‘https://pizza-and-desserts.p.rapidapi.com/pizzas’, headers: { ‘X-RapidAPI-Host’: ‘pizza-and-desserts.p.rapidapi.com’, ‘X-RapidAPI-Key’: your rapid api key }).then(res=>res.json()).then(data=>console.log(data)).catch(e=>console.log(e))
hope this helps you
API Pizza
get URL?
How to collect a URL?
i don’t understand your question…
ディスカッションに参加しましょう-以下にコメントを追加してください:
the url is:
for pizzas= url: ‘https://pizza-and-desserts.p.rapidapi.com/pizzas’
for desserts= url: ‘https://pizza-and-desserts.p.rapidapi.com/desserts’
headers: {
‘X-RapidAPI-Host’: ‘pizza-and-desserts.p.rapidapi.com’,
‘X-RapidAPI-Key’: your rapid api key
example:
fetch(‘https://pizza-and-desserts.p.rapidapi.com/pizzas’,
headers: {
‘X-RapidAPI-Host’: ‘pizza-and-desserts.p.rapidapi.com’,
‘X-RapidAPI-Key’: your rapid api key
}).then(res=>res.json()).then(data=>console.log(data)).catch(e=>console.log(e))
API Pizza
get URL?
How to collect a URL?
i don’t understand your question…