seo api

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Increase number of responses per request or Increase number of requests

Rapid account: Allubharadwajyadav

query ={“q”:“data scientist”, “num”: 20}
dic = dict()

resp = requests.get(“https://seo-api.p.rapidapi.com/v1/job/search/” + urllib.parse.urlencode(query), headers=headers)

results = resp.json()

I want to increase the number of responses per request or increase the #requests made. The num parameter doesn’t seem to be working. Can you suggest a way to modify the above query so that I can retrieve say like 100 or more results.

Rapid account: Allubharadwajyadav
allubharadwajyadav Commented un anno fa

Thanks!

Rapid account: Serply
Serply Commented un anno fa

Hello.

The jobs API does not support the num parameter. Theres no way to get more than 10 results at a time. However you can page through the results using the start parameter. To get results 10-20. You would use start=10

Hope this helps.
Team Serply

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