how can i pass one url to the parameter file?

This is my code:

header(‘Access-Control-Allow-Origin:*’);
$headers = apache_request_headers();

$file = “www.accyscloud.com/acs/_lib/file/doc/2006/CSF_TEC.pdf”;

$curl = curl_init();

curl_setopt_array(curl, [ CURLOPT_URL => "https://pdf-to-text-converter.p.rapidapi.com/api/pdf-to-text/convert", CURLOPT_RETURNTRANSFER => true, CURLOPT_FOLLOWLOCATION => true, CURLOPT_ENCODING => "", CURLOPT_MAXREDIRS => 10, CURLOPT_TIMEOUT => 30, CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1, CURLOPT_CUSTOMREQUEST => "POST", CURLOPT_POSTFIELDS => "-----011000010111000001101001\r\nContent-Disposition: form-data; name=\"file"\r\n\r\n\r\n-----011000010111000001101001\r\nContent-Disposition: form-data; name=“page”\r\n\r\n1\r\n-----011000010111000001101001–\r\n\r\n",
CURLOPT_HTTPHEADER => [
“X-RapidAPI-Host: pdf-to-text-converter.p.rapidapi.com”,
“X-RapidAPI-Key: 20279164dbmshb8e4669f4336a23p10ab3ejsnd93eb2fcd7e2”,
“content-type: multipart/form-data; boundary=—011000010111000001101001”
],
]);

$response = curl_exec($curl);
$err = curl_error($curl);

curl_close($curl);

if ($err) {
echo “cURL Error #:” . $err;
} else {
echo $response;
}

Thanks and regards!