Повернутися до всіх обговорень
Increase number of responses per request or Increase number of requests
allubharadwajyadav
a year ago
query ={“q”:“data scientist”, “num”: 20}
dic = dict()
resp = requests.get(“https://seo-api.p.rapidapi.com/v1/job/search/” + urllib.parse.urlencode(query), headers=headers)
results = resp.json()
I want to increase the number of responses per request or increase the #requests made. The num parameter doesn’t seem to be working. Can you suggest a way to modify the above query so that I can retrieve say like 100 or more results.
Приєднуйтесь до обговорення — додайте повідомлення нижче:
Вхід / Реєстрація, щоб публікувати нові повідомлення
Thanks!
Hello.
The jobs API does not support the num parameter. Theres no way to get more than 10 results at a time. However you can page through the results using the
startparameter. To get results 10-20. You would usestart=10Hope this helps.
Team Serply